By Falko Lorenz

ISBN-10: 0387316086

ISBN-13: 9780387316086

The current textbook is a full of life, problem-oriented and punctiliously written advent to classical sleek algebra. the writer leads the reader via attention-grabbing subject material, whereas assuming simply the historical past supplied by means of a primary direction in linear algebra.

The first quantity specializes in box extensions. Galois thought and its functions are handled extra completely than in such a lot texts. It additionally covers easy functions to quantity thought, ring extensions and algebraic geometry.

The major concentration of the second one quantity is on extra constitution of fields and comparable issues. a lot fabric now not frequently coated in textbooks appears to be like right here, together with actual fields and quadratic kinds, diophantine dimensions of a box, the calculus of Witt vectors, the Schur team of a box, and native classification box theory.

Both volumes include a number of routines and will be used as a textbook for complicated undergraduate scholars.

**Read Online or Download Algebra, Volume 1: Fields and Galois Theory (Universitext) PDF**

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**Extra info for Algebra, Volume 1: Fields and Galois Theory (Universitext)**

**Sample text**

In the remainder of this chapter, R will always be an integral domain. Question (i) above can be generalized to read: When is RŒX a UFD? For practice with basic algebraic constructs, we start by establishing the following: F1. RŒX is a principal ideal domain if and only if R is a ﬁeld. Proof. If R D K is a ﬁeld, KŒX is a Euclidean domain and therefore a principal ideal domain (Chapter 4, F6). 46 5 Prime Factorization in Polynomial Rings. Gauss’s Theorem Conversely, assume RŒX is a principal ideal domain.

Gauss’s Theorem Conversely, assume RŒX is a principal ideal domain. Consider the kernel I of the substitution homomorphism ' W RŒX ! X / D 0. X /. Thus (1) RŒX =X D RŒX =I ' R is an integral domain, that is, X is prime in RŒX , by Deﬁnition 9 of Chapter 4. But then the next statement shows that RŒX =X is actually a ﬁeld, and therefore by (1) R is also a ﬁeld. ˜ F2. If A is a principal ideal domain and ﬁeld. is irreducible in A, the quotient A= is a Proof. According to F14 in Chapter 4, we have to show that .

Let R be an integral domain and let a ‘ a be a homomorphism of R into an integral domain R; extend this to a homomorphism RŒX ! RŒX of polynomial rings in the usual way: X X ai X i : f D ai X i ‘ f D 50 5 Prime Factorization in Polynomial Rings. X / D an X n C C a0 be a primitive polynomial of RŒX with an ¤ 0. If f is irreducible in RŒX , then f is irreducible in RŒX . Proof. Assume the opposite. Then f D gh, where g; h are nonconstant polynomials in RŒX (nonconstant because f is primitive).

### Algebra, Volume 1: Fields and Galois Theory (Universitext) by Falko Lorenz

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